6. Z 字形变换
将一个给定字符串 s
根据给定的行数 numRows
,以从上往下、从左到右进行 Z 字形排列。
比如输入字符串为 "PAYPALISHIRING"
行数为 3
时,排列如下:
P A H N
A P L S I I G
Y I R
之后,你的输出需要从左往右逐行读取,产生出一个新的字符串,比如:"PAHNAPLSIIGYIR"
。
请你实现这个将字符串进行指定行数变换的函数:
string convert(string s, int numRows);
示例
示例 1
输入:s = "PAYPALISHIRING", numRows = 3
输出:"PAHNAPLSIIGYIR"
示例 2
输入:s = "PAYPALISHIRING", numRows = 4
输出:"PINALSIGYAHRPI"
示例 3
输入:s = "A", numRows = 1
输出:"A"
提示
1 <= s.length <= 1000
s 由英文字母(小写和大写)、',' 和 '.' 组成
1 <= numRows <= 1000
代码
javascript
// 输入:s = "PAYPALISHIRING", numRows = 3
// 输出:"PAHNAPLSIIGYIR"
export function convert(s, numRows) {
if (numRows === 1 || numRows > s.length) return s
const resObj = {}
let rowIndex = 0
let rowLine = 1
for (let i = 0; i < s.length; i++) {
resObj[String(rowIndex)] = resObj[String(rowIndex)] ? `${resObj[String(rowIndex)]}${s[i]}` : s[i]
if (rowIndex === numRows - 1) rowLine = -1
if (rowIndex === 0) rowLine = 1
rowIndex = rowIndex + rowLine
}
let res = ''
for (let i = 0; i < numRows; i++) {
res = `${res}${resObj[String(i)]}`
}
return res
}
typescript
// 输入:s = "PAYPALISHIRING", numRows = 3
// 输出:"PAHNAPLSIIGYIR"
export function convert(s: string, numRows: number): string {
if (numRows === 1 || numRows > s.length) return s
const resObj: { [key: string]: string } = {}
let rowIndex = 0
let rowLine = 1
for (let i = 0; i < s.length; i++) {
resObj[String(rowIndex)] = resObj[String(rowIndex)] ? `${resObj[String(rowIndex)]}${s[i]}` : s[i]
if (rowIndex === numRows - 1) rowLine = -1
if (rowIndex === 0) rowLine = 1
rowIndex = rowIndex + rowLine
}
let res = ''
for (let i = 0; i < numRows; i++) {
res = `${res}${resObj[String(i)]}`
}
return res
}
测试代码
ts
import { expect, test } from 'vitest'
import { convert } from './typescript.ts'
import { convert as convertJs } from './javascript.js'
test(`PAYPALISHIRING`, () => {
expect(convert('PAYPALISHIRING', 3)).toEqual('PAHNAPLSIIGYIR')
})
test(`PAYPALISHIRING`, () => {
expect(convertJs('PAYPALISHIRING', 3)).toEqual('PAHNAPLSIIGYIR')
})