83. 删除排序链表中的重复元素
给定一个已排序的链表的头 head , 删除所有重复的元素,使每个元素只出现一次 。返回 已排序的链表 。
示例
示例1
输入:head = [1,1,2]
输出:[1,2]
示例2
输入:head = [1,1,2,3,3]
输出:[1,2,3]
提示
- 链表中节点数目在范围 [0, 300] 内
- -100 <= Node.val <= 100
- 题目数据保证链表已经按升序 排列
代码
javascript
export function ListNodeJs(val, next) {
this.val = (val === undefined ? 0 : val)
this.next = (next === undefined ? null : next)
}
typescript
export class ListNode {
val: number
next: ListNode | null
constructor(val?: number, next?: ListNode | null) {
this.val = (val === undefined ? 0 : val)
this.next = (next === undefined ? null : next)
}
}
javascript
// 83. 删除排序链表中的重复元素
// https://leetcode.cn/problems/remove-duplicates-from-sorted-list/description/
export function deleteDuplicates(head) {
if (!head) {
return head;
}
let cur = head;
while (cur.next) {
if (cur.val === cur.next.val) {
cur.next = cur.next.next;
} else {
cur = cur.next;
}
}
return head;
};
typescript
// 83. 删除排序链表中的重复元素
// https://leetcode.cn/problems/remove-duplicates-from-sorted-list/description/
import { ListNode } from "../../utils"
export function deleteDuplicates(head: ListNode | null): ListNode | null {
if (!head) {
return head;
}
let cur = head;
while (cur.next) {
if (cur.val === cur.next.val) {
cur.next = cur.next.next;
} else {
cur = cur.next;
}
}
return head;
};
测试代码
ts
import { expect, test } from 'vitest'
import { getListNode } from "../../../src/utils"
import { deleteDuplicates } from './typescript.ts'
import { getListNodeJs } from "../../../src/utilsJs"
import { deleteDuplicates as deleteDuplicatesJs } from './javascript.js'
const a1 = [1, 1, 2]
const a2 = [1, 2]
const aL1 = getListNode(a1)
const aL2 = getListNode(a2)
test(`deleteDuplicates(aL1) toEqual aL2`, () => {
expect(deleteDuplicates(aL1)).toEqual(aL2)
})
const a3 = [1, 1, 2, 3, 3]
const a4 = [1, 2, 3]
const aL3 = getListNode(a3)
const aL4 = getListNode(a4)
test(`deleteDuplicates(aL3) toEqual aL4`, () => {
expect(deleteDuplicates(aL3)).toEqual(aL4)
})
const a5 = [1, 1, 2]
const a6 = [1, 2]
const aL5 = getListNodeJs(a5)
const aL6 = getListNodeJs(a6)
test(`deleteDuplicatesJs(aL5) toEqual aL6`, () => {
expect(deleteDuplicatesJs(aL5)).toEqual(aL6)
})
const a7 = [1, 1, 2, 3, 3]
const a8 = [1, 2, 3]
const aL7 = getListNodeJs(a7)
const aL8 = getListNodeJs(a8)
test(`deleteDuplicatesJs(aL7) toEqual aL8`, () => {
expect(deleteDuplicatesJs(aL7)).toEqual(aL8)
})